The distance from \((h, k)\) to \(x=1\) is \(1-h\)
To reflect across the line, we go twice this distance, which is \(2-2h\)
So the new x-coordinate is \(h+(2-2h)=2-h\)
\(A (-8, -6)\) becomes \(A' (2-(-8), -6)=(10, -6)\)
\(B (-2, -6)\) becomes \(B' (2-(-2), -6)=(4, -6)\)
\(C (-5, -4)\) becomes \(C' (2-(-5), -6)=(7, -6)\)
