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Verified Answer :

Willchemistry

1 mole ----------- 22.4 L ( at STP )
3.75 moles ----- ?

3.75 x 22.4 / 1 => 84.0 L

Answer : The volume of oxygen gas is 84.0 liters.

Explanation : Given,

Moles of oxygen gas = 3.75 moles

Now we have to determine the volume of oxygen gas at STP.

As we know that at STP, 1 mole of substance occupies 22. 4 L volume of gas.

As, 1 mole of \(O_2\) gas occupies 22.4 L volume of \(O_2\) gas

So, 3.75 moles of \(O_2\) gas occupies \(3.75\times 22.4=84.0L\) volume of \(O_2\) gas

Therefore, the volume of oxygen gas is 84.0 liters.

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