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leeandrews2

when you multiply exponents, Your add them so you need to add 4 and 2 to get 6. The answer would be C

calculista

we have

\((5a^{2} b^{3} )(6a^{k}b)=30 a^{6}b^{4}\)

Multiply the left side and then compare with the right side

\((5a^{2} b^{3} )(6a^{k}b)\)

Combine like terms

\((5*6)(a^{2}*a^{k})(b^{3}*b)\\=(30)(a^{k+2})(b^{4})\)

Compare with the right side

\((30)(a^{k+2})(b^{4})=30 a^{6}b^{4}\)

so

\((a^{k+2})=a^{6}\)

\(k+2=6\)

solve for k

\(k=6-2=4\)

therefore

the answer is the option C

\(4\)

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