How fast would a ball have to be thrown upward to reach a maximum height of 100ft? (Hint: Use the discriminant of the equation, 16T^2-voT+h=0)

I dont understand when to use a discriminant and why, what does the discriminant tell you?

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Anonymous Anonymous · Answer 1 · 2016-11-12T14:59:46-05:00

I hope this helps you

16t^2-vot+100=0

(4t-10)^2=0

4t-10=0

4t=10

t=5/2

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shivishivangi1679 shivishivangi1679 · Answer 2 · 2022-07-27T05:51:20-04:00

A ball have to be thrown 5/2 sec fast upward to reach a maximum height of 100ft.

A quadratic equation is the second-order degree algebraic expression in a variable.

The standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

From the given expression;

16T^2-voT+h=0

To reach a maximum height of 100ft.

16t^2 - voT + 100 = 0

(4t-10)^2 = 0

4t - 10 = 0

4t = 10

t=5/2

A ball have to be thrown 5/2 sec fast upward to reach a maximum height of 100ft.

Learn more about quadratic equations;

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