How many liters of 0.1107 M KCI contains 15.00 g of KCI (FW= 74.6 g/mol)
Number of moles:
n = sample mass / molar mass
n = 15.00 / 74.6
n = 0.2010 moles of KCl
Therefore:
Molarity = moles / Volume
0.1107 = 0.2010 / V
V = 0.2010 / 0.1107
V = 1.815 L
Answer:
1.81 liters of KCl solution
Explanation:
Molarity is expressed as:
\(Molarity=\frac{molesofsolute}{litersofsolution}\)
Solving for Liters of solution:
Liters of solution = \(\frac{molesofsolute}{Molarity}\) (1)
Using the molecular weight fo the KCl to find the moles of solute:
\(15.00gKCl*\frac{1molKCl}{74.6gKCl}=0.20molesKCl\)
Replacing in the formula (1):
Liters of solution = \(\frac{0.20molesKCl}{0.1107M}\)
Liters of solution = 1.81 liters