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Solve 6 over x minus 6 equals the quantity of x over x minus 6, minus six halves. for x and determine if the solution is extraneous or not.

Verified Answer :

First, let us express it into a mathematical equation:

\(\frac{6}{x} -6=( \frac{x}{x-6} )- \frac{6}{2}\)

Then we simplify the equation by combining like terms

\(\frac{6}{2} -6=( \frac{x}{x-6} )- \frac{6}{x}\)

\(-3 = \frac{ x^{2} -6(x-6)}{x(x-6)}\)

\(-3 = \frac{ x^{2} -6x+36}{x(x-6)}\)

\(-3 = \frac{ x^{2} -6x+36}{x(x-6)}\)

\(-3x(x-6) = x^{2} -6x+36\)

\(-3 x^{2} +18x = x^{2} -6x+36\)

\(-3 x^{2} - x^{2} +6x-36+18x =0\)

\(-4 x^{2} +24x-36 =0\)

\((-4 x^{2} +24x-36 =0)/-4\)

\(x^{2}-6x+9 =0\)

\((x-3)^{2} =0\)

x = 3

There is a solution so it is not extraneous.