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Suppose the series Σ cn xn has radius of convergence 2 and the series Σ dn xn has radius of convergence 3. What is the radius of convergence of the series Σ (cn + dn)xn?

Verified Answer :

I normally don't do these things but I believe the answer is sn2x • (c + d).

An intersection, or in this case, the much more limited radius of convergence, is the radius of convergence. You apply the same logic to domains of functions.

Finding the domain:

\(\to f(x) = \sin(\ln(x))\)

  • The function \(\sin(x)\) has a domain of \((-\infty, \infty)\). \(\ln(x)\) is a domain name \("0, \infty"\).
  • All values for which \(\ln(x) \ \ and\ \ \sin(x)\) both describe the domain of \(f(x)\). It must be in this scenario "\(0, \infty\)".
  • \(f(x) = \sin(x) + \ln(x).\) The name of the website would be "\(0, \infty\)"
  • Whenever you say a function does have a radius of convergence \((R)\), you're implying that all converge again for the following values:
  • You say \(|x| < R\), but you also say \(|x| > R\).
  • For \(|x| < 2.\), one function converges, while for \(|x| < 3\), the other converges.
  • The most stringent are: \(|x| < 2.\)
  • The total of the series' radius of convergence is: \(R=2\)

Find out more information about the radius of convergence here:

brainly.com/question/23558817