the sum of the root of 3x^2+11x-4=0
the sum of the root of 3x^2+11x-4=0
A product of several terms equals zero. When a product of two or more terms equals zero, then at least one of the terms must be zero. We shall now solve each term = 0 separately. In other words, we are going to solve as many equations as there are terms in the product. Any solution of term = 0 solves product = 0 as well.
Solve : 3x-1 = 0
Add 1 to both sides of the equation :
3x = 1
Divide both sides of the equation by 3:
x = 1/3 = 0.333
Solve : x+4 = 0 Subtract 4 from both sides of the equation : x = -4
x = -4 and x = 1/3 or 0.333
Answer:
Option (a) is correct.
The sum of roots of given quadratic equation \(-\frac{11}{3}\)
Step-by-step explanation:
Given quadratic equation \(3x^2+11x+4=0\)
We have to find the sum of roots.
Consider the given quadratic equation \(3x^2+11x+4=0\)
For a given standard quadratic equation \(ax^2+bx+c=0\) , we have
Sum of roots is given by \(-\frac{b}{a}\)
and product of roots is given by \(\frac{c}{a}\)
Thus, for the given quadratic equation \(3x^2+11x+4=0\)
a = 3 , b = 11 , c = 4
So, the sum of roots is given by \(-\frac{b}{a}\)
Substitute, we get,
Thus, The sum of roots of given quadratic equation \(-\frac{11}{3}\)