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Verified Answer :

The answer is a
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Answer:

Option A  \(-4\) and \(0\)

Step-by-step explanation:

we have

\(x^{2}+y^{2} =16\) -----> equation A

This is the equation of a circle with center at the origin and radius \(4\) units

\(y=x+4\) -----> equation B

This is the equation of a line

we know that

The solution of the system of equations is the intersection point both graphs

using a graphing tool

The intersection points are \((-4,0)\) and \((0,4)\)

see the attached figure

therefore

the x-coordinates of the solution are \(-4\) and \(0\)

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