Answered

Find the distance, in meters, a particle travels in its first 10 seconds of travel, if it moves according to the velocity equation v(t)= 49 _ 9.8t (in meters/sec).


A: _49

B: 0

C: 245

D: 441

Verified Answer :

Nirina7

the distance can be found with integ (v(t)= integ(49 _ 9.8t= 49t _ 9.8 /2 t^2
so D(t) = 49t _ 9.8 /2 t^2, for t = 10s, D = 49x10 _ 9.8 /2 x 100 =441
D = 441

Answer:

245

Step-by-step explanation:

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