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Nirina7

let be y= world, and joy=x
so we have integral (world)joy^world-1d(joy) = integ(yx^y-1)dx, y is a constant independant of x, so integ(yx^y-1)dx = y . integ(x^y-1)dx
=y .(x^y-1+1 / y-1 +1) + C=(x^y) + C

the answer is joy^world

Answer:

The answer is \(joy^{world} + C\)

Step-by-step explanation:

Given the indefinite integral \(\int (world)joy^{world-1}d(joy)\)

Let world → a

         joy → x

Therefore, the integral becomes \(\int ax^{a-1}dx\)

                                                    = \(a\frac{x^{a-1+1} }{a-1+1} + C\)

                                                    = \(x^{a} + C\)

Replacing, a → world

                  x → joy  

Hence, \(\int (world)joy^{world-1}d(joy)\) = \(joy^{world} + C\)

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