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A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 10.0cm , giving it a charge of -15.0_C .




A: Find the electric field just inside the paint layer.

B: Find the electric field just outside the paint layer.

C: Find the electric field 6.00cm outside the surface of the paint layer.

Verified Answer :

syed514

(1/4πϵ0)q/r2=(9∗109)∗(−15)/(0.06∗0.06)=3.75∗1013newton/coloumEdA=qenclosedϵ0
EA=qenclosedϵ0
E(4πr2)=qenclosedϵ0
E=qenclosed(4πr2)ϵ0
E=−15X10−6C(4π(5X10−2+6X10−2)2)ϵ0roadjester  3 years agoI converted the radius to meters
You want the electric field 6cm outside of the sphere so the radius is 5 cm (half of the diameter of the sphere) plus the 6cm so the net radius is actually 11c

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