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Two paramedics are lifting a person on a stretcher. One of the paramedics exerts a force of 350 N at 58o above the horizontal and the other exerts a force of 410 N at 43o above the horizontal. What is the weight of the person and the stretcher?

Verified Answer :

Fy = Fy1 + Fy2

Fy = 350sin(58) + 410sin(43)

Fy = 576.44 N

tailohrcampbell


 F1 = 350 N
 q1 = 58.0°
 F2 = 410 N

q2 = 43°
 Fy,net = F1(sin q1) + F2(sin q2) = (350 N)(sin 58°) + (410 N)(sin 43)
 Fy,net = 3.0 × 102 N + 2.8 × 102 N
Fy,net = 580 N

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