Answer:
The period of cot function is \(\pi\)
Step-by-step explanation:
Given : \(y=\cot x\)
To find : What is the period?
Solution :
Using the general form of the cot trigonometric function
\(y=a\cot (bx-c)+d\)
Where, a=1,b=1,c=0,d=0
Now, The period of the function formula is
\(P=\frac{\pi}{b}\)
The value of b=1,
\(P=\frac{\pi}{1}\)
\(P=\pi\)
Therefore, The period of cot function is \(\pi\)
