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A particular form of electromagnetic radiation has a frequency of 8.11 x 10^14 hz. What is the energy in joules of one quantum of this radiation?

Verified Answer :

E = hxf, où h = constante de Planck = 6,626 x 10 ^ -34Js 

E = 6,626 x 10 ^ -34 x 8.11 x 10 ^ 14 = 5.373 10^ -19 J 
 

Hope this answers your question, Kimmyers14!

aachen

Answer:

Energy, \(E=5.37\times 10^{-19}\ J\)

Explanation:

The frequency of the electromagnetic radiation, \(f=8.11\times 10^{14}\ hz\)

We need to find the energy of one quantum of this radiation. The energy and frequency follows the following relationship as :

\(E=h\times f\)

\(E=6.63\times 10^{-34}\times 8.11\times 10^{14}\)

\(E=5.37\times 10^{-19}\ J\)

So, the energy of one quantum of this radiation \(5.37\times 10^{-19}\ J\). Hence, this is the required solution.