A particular form of electromagnetic radiation has a frequency of 8.11 x 10^14 hz. What is the energy in joules of one quantum of this radiation?
E = hxf, où h = constante de Planck = 6,626 x 10 ^ -34Js
E = 6,626 x 10 ^ -34 x 8.11 x 10 ^ 14 = 5.373 10^ -19 J
Hope this answers your question, Kimmyers14!
Answer:
Energy, \(E=5.37\times 10^{-19}\ J\)
Explanation:
The frequency of the electromagnetic radiation, \(f=8.11\times 10^{14}\ hz\)
We need to find the energy of one quantum of this radiation. The energy and frequency follows the following relationship as :
\(E=h\times f\)
\(E=6.63\times 10^{-34}\times 8.11\times 10^{14}\)
\(E=5.37\times 10^{-19}\ J\)
So, the energy of one quantum of this radiation \(5.37\times 10^{-19}\ J\). Hence, this is the required solution.