Answer : The energy of one photon is \(4.65\times 10^{-19}J\)
Explanation : Given,
Frequency of blue light = \(7.02\times 10^{14}Hz=7.02\times 10^{14}s^{-1}\)
Formula used :
\(E=h
u\)
where,
\(u\) = frequency of blue light
h = Planck's constant = \(6.626\times 10^{-34}Js\)
E = energy of one photon = ?
Now put all the given values in the above formula, we get:
\(E=(6.626\times 10^{-34}Js)\times (7.02\times 10^{14}s^{-1})\)
\(E=4.65\times 10^{-19}J\)
Therefore, the energy of one photon is \(4.65\times 10^{-19}J\)
