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Willchemistry

Molar mass MgCl2 = 95.211 g/mol

number of moles:

1 mole ---------- 95.211 g
? moles --------- 78.6 g

78.6 x 1 / 95.211 => 0.8255 moles

Therefore:

M = n / V

M = 0.8255 / 1.00

M = 0.8255 mol/L

Answer:  Molarity of the solution is 0.83 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

\(Molarity=\frac{n}{V_s}\)

where,

n= moles of solute

\(Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{78.6g}{95g/mol}=0.83mole\)

\(V_s\) = volume of solution  in L

\(Molarity=\frac{0.83moles}{1L}=0.83M\)

Thus the molarity of the solution is 0.83 M

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