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The quadratic equation y = –6x2 + 100x – 180 models the store’s daily profit, y, for selling soccer balls at x dollars. The quadratic equation y = –4x2 + 80x – 150 models the store’s daily profit, y, for selling footballs at x dollars. Use a graphing calculator to find the intersection point(s) of the graphs, and explain what they mean in the context of the problem

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Answer:

Step-by-step explanation:

The quadratic equation    \(y = -6x^2 + 100x - 180\)        models the store’s daily profit, y, for selling soccer balls at x dollars.

The quadratic equation    \(y = -4x^2 + 80x - 150\)    models the store’s daily profit, y, for selling footballs at x dollars.

Now we are supposed to find the intersection point(s) of the graphs using graphing calculator

Refer the attached graph.

\(y = -6x^2 + 100x - 180\)   -- Green line

\(y = -4x^2 + 80x - 150\)    -- Purple line

So, from the graph we can see there are two intersection points :

(8.333,236.667)

(2.053,0)

So, from solution (8.333,236.667) we depict that at x = 8.333 dollars the store's daily profit y = 236.667 for selling football or soccer ball.

From solution (2.053,0)we depict that at x = 0 dollars the store's daily profit y = 2.053 for selling football or soccer ball.

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Answer:

see explanation

Step-by-step explanation:

The quadratic equation            models the store’s daily profit, y, for selling soccer balls at x dollars.The quadratic equation        models the store’s daily profit, y, for selling footballs at x dollars.Now we are supposed to find the intersection point(s) of the graphs using graphing calculatorRefer the attached graph.   -- Green line    -- Purple line So, from the graph we can see there are two intersection points :(8.333,236.667)(2.053,0)So, from solution (8.333,236.667) we depict that at x = 8.333 dollars the store's daily profit y = 236.667 for selling football or soccer ball.From solution (2.053,0)we depict that at x = 0 dollars the store's daily profit y = 2.053 for selling football or soccer ball.

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