2H2 + O2 --> 2H2O If 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?
Start out with your given so that's 16 moles of O2. For every one mole of O2, there are 2 moles of H2O
(16 mol O2)* (2molesH2O/1molO2) = 32 moles of H2O
Answer:
32 moles of water
Explanation:
From the reaction, we can deduce that 1 mole of oxygen gas (O2) was used to produce 2 moles of water (H2O).
Hence, 16 moles of oxygen will produce "X" moles of water (where X is the unknown).
1 mole of O2 ⇒ 2 moles of H2O
16 moles of O2 ⇒ X
X = \(\frac{16 * 2}{1}\) = 32 moles of H2O
16 moles of O2 will produce 32 moles of H2O