Simple...
you have: \(\frac{n}{3} =12\)
and
\(\frac{n}{3} =-12\)
To solve for....\(\frac{n}{3} =12\)
Multiply to remove the denominator-->>
\(3* \frac{n}{3} =12*3\)
n=123
n=36
Then-->>>
\(\frac{n}{3} =-12\)
Do the same thing-->>
\(3* \frac{n}{3} =-12*3\)
n=-123
n=-36
Thus, your answer.
