evaluate f(x)=12x+1 when x=-2,0,and 3
For function f(x) = 12x + 1,
f(-2) = -23
f(0) = 1
f(3) = 37
For given question,
We have been given a function f(x) = 12x + 1
We need to find the value of a function when x = -2, 0, and 3
When x = -2,
⇒ f(-2) = 12(-2) + 1
⇒ f(-2) = -24 + 1
⇒ f(-2) = -23
When x = 0,
⇒ f(0) = 12 × (0) + 1
⇒ f(0) = 0 + 1
⇒ f(0) = 1
When x = 3,
⇒ f(3) = 12(3) + 1
⇒ f(3) = 36 + 1
⇒ f(3) = 37
Therefore, for function f(x) = 12x + 1,
f(-2) = -23
f(0) = 1
f(3) = 37
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