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Verified Answer :

Answer:

The solution set of the equation are (2,0) and (-12,0)

Step-by-step explanation:

Given : Equation \(x^2+10x=24\)

To find : Solve equation by completing the square ?

Solution :

The general form of quadratic equation is \(ax^2+bx+c=0\)

So, \(x^2+10x-24=0\)

To complete the square we add and subtract \((\frac{b}{2})^2\)

i.e. \((\frac{b}{2})^2=(\frac{10}{2})^2=5^2\)

Applying in equation,

\(x^2+10x-24+5^2-5^2=0\)

Re-writ equation as,

\(x^2+2\times 5\times x+5^2-24-25=0\)

Apply \(a^2+2ab+b^2=(a+b)^2\)

\((x+5)^2-49=0\)

\((x+5)^2=49\)

Taking root both side,

\(x+5=\pm \sqrt{49}\)

\(x+5=\pm 7\)

\(x+5=7\) or \(x+5=-7\)

\(x=2\) or \(x=-12\)

Therefore, the solution set of the equation are (2,0) and (-12,0)

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Answer:

The correct answer is C!!!

I hope this  helps you out, have an amazing day

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