Simple...
you have: \(F= \sqrt[a]{ \frac{ 16a^{2} + 8a^{2} }{ 4a^{2}+ 2a^{2} } }\)
As far as I can see this is pretty simple....
Simply divide it-->>>>
the \(a^{2}\) cancel out-->>
\(F= \sqrt[a]{ \frac{24}{6} }\)
\(F= \sqrt[a]{4}\)
Thus, your answer.
