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Find the indicated limit, if it exists.


limit of f of x as x approaches negative 8 where f of x equals x plus 9 when x is less than negative 8 and f of x equals negative seven minus x when x is greater than or equal to negative 8


-8

1

17

The limit does not exist.

Verified Answer :

Find \({\displaystyle\lim_{x \rightarrow ~-8}f(x)}\)

where \({ f(x) = \begin{cases} & x+9,~~~~~~~~~~{\large x\ \textless \ -8} \\ & -7-x,~~~~~~{\large x\ge-8} \end{cases} }\)

So to find the left sided limit, you need to plug in -8, into x+9
and to find the right sided limit, you need to plug in -8, into -7-x.

If the two sides of the limit are no equivalent, then \({\displaystyle\lim_{x \rightarrow ~-8}f(x)~~DNE}\)

Since both sides are equal to 1, the limit is 1.

Answer:

1

Step-by-step explanation:

just took the test