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1.If a 40 kg person is accelerating at 10 m/s2, then the force acting on him or her is 400 N

Atrue or B.false

2.How much force is needed to make a 60 kg object accelerate at a rate of 2.0 m/s2?

A62 N

B.62 kg

C.120 N

D.120 kg

3.What is the acceleration of a 30 kg object when 180 N of force is applied to it?

A.6.0 m/s2

B.60 m/s2

C.210 m/s2

D.5,400 m/s2

4.Which of the following equations show how you would solve for mass if you knew the force acting on an object & the acceleration of an object?

A.m=f/a

B.m= fa

C.m=a/f

D.m=f-a

Verified Answer :

scme1702

In all of the questions, we apply Newton's second law that:
Force = mass x acceleration
1) A. True

2) C, 120 N; F = 60 x 2 = 120N

3) A, 6 m/s²; a = F/m = 180/30 = 6

4) A; F = ma → m = F/a

Answer: 1) The given statement is true.

2 .The correct answer is option C.

3.The correct answer is option A.

4.The correct answer is option A.

Explanation:

1. Mass of the person = m = 40 kg

Rate of acceleration of person = a = \(10 m/s^2\)

Force on the person =  \(F=mass\times acceleration = 40 kg\times 10 m/s^2=400 N\)

True, the force acting on him or her is 400 N.

2.Mass of an object ,m= 60 kg

Rate of acceleration of an object ,a= \(a=2.0 m/s^2\)

Force required:

\(F=m\times a=60 kgtimes 2.0 m/s^2=120.0 N\)

Hence, the correct answer is option C.

3. Mass of an object ,m= 30 kg

Force applied ,F = 180 N

Let rate of the acceleration be = a

\(F=m\times a\)

\(a=\frac{180 N}{30 Kg}=6.0 m/s^2\)

Hence, the correct answer is option A.

4. If we know the force acting on an object along with acceleration of an object.

From the formula: F= ma

Mass can be determined by:

\(m=\frac{F}{a}\)

Hence, the correct answer is option A.

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