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Verified Answer :

HomertheGenius

We have to rewrite the expression so that it has no denominator.
For example:
1 / x = x^(-1)
1/8 = 8^(-1); 1/x^(4) = x^(-4); 1/y^(3) = y^(-3); 1/z = z^(-1).
\(\frac{3a ^{2} b ^{3}c ^{5} }{8 x^{4}y ^{3}z }= \\ =3 a^{2}b ^{3}c^{5}8^{-1}x ^{-4}y^{-3}z^{-1}\)

meaganblatcher

Answer:

\(3 * 2^{-3}a^{2}b^{3}c^{5}x^{-4}y^{-3}z\)

Step-by-step explanation:

you take away 8 and multiply  and get 3a^2b^3c^5 x^4y^3z or something

This becomes 3a^2b^3c^5x^-4y^-3z/8

Then you move the 8 up using multiplication and get -24a^2b^3c^5x^4y^3z

This can be simplifed as 32^-3a^2b^3c^5x^-4y^-3z

regardless that's the real answer.

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