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simplify the radical expression.

  1. Ì250h^4k^5

  2. Ì14q x 2Ì4q




  3. Ì63x^15y^9/7xy^11




  4. Ì3+4Ì3

5Ì6

5Ì3

3Ì6

3Ì3




  1. 2Ì6+3Ì96

14Ì6

14Ì96

5Ì96

50Ì6



  1. (8 +Ì11 )(8 _Ì11 )

53

75 + 16Ì11

_57

64 + Ì11

Verified Answer :

  1. \(\sqrt{250h^4k^5} = \sqrt{25 \times 10 (h^2)^2(k^2)^2k} = \sqrt{(5h^2k^2)^2\times 10k}=5h^2k^2\sqrt{10k}\)

    6. \(\sqrt{14q} \times 2\sqrt{4q}=2 \sqrt{14q} \sqrt{4q}=2 \sqrt{14q4q} =2 \sqrt{14\times2^2q^2} =2\times2q \sqrt{14} = \\=4q \sqrt{14}\)

    7. \(\sqrt{ \frac{63x^{15}y^9}{7xy^{11}}}= \sqrt{ \frac{9x^{14}}{y^2}}= \frac{3x^7}{y}\)

    8. \(\sqrt{3} +4 \sqrt{3} =5 \sqrt{3}\)

    9. \(2 \sqrt{6} +3 \sqrt{96}=2 \sqrt{6} +3 \sqrt{6\times16}= 2 \sqrt{6} +3 \times 4\sqrt{6}= \\= 2 \sqrt{6} +12\sqrt{6}= 14 \sqrt{6}\)

    10. \((8+ \sqrt{11} )(8- \sqrt{11} )=8^2- \sqrt{11} ^2=64-11=53\)

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