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The molar mass of NaOH is 40.00 g/mol. If 5.20 g NaOH are dissolved in 0.500 L of solution, what is the molarity of the solution?

0.0125 M

0.260 M

3.85 M

7.69 M

Verified Answer :

 The molarity   of the solution is  0.260 M

 calculation

step 1: calculate  the moles of NaOH

moles  = mass÷ molar mas

= 5.20 g÷ 40.00 g/mol= 0.13  moles

Step 2: find the molarity of solution

molarity = moles÷volume  in liters

=0.13  moles÷ 0.500 L = 0.260 M

Taking into account the definition of molarity, the molarity of the solution is 0.26 M.

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

\(molarity=\frac{number of moles}{volume}\)

Molarity is expressed in units \(\frac{moles}{liter}\).

This case

In this case, you know:

  • number of moles= 5.20 g× \(\frac{1 mol}{40 g}\)= 0.13 moles (being 40 g/mol the molar mass of NaOH)
  • volume= 0.500 L

Replacing in the definition of molarity:

\(molarity=\frac{0.13 moles}{0.500 L}\)

Solving:

molarity= 0.26 M

Finally, the molarity of the solution is 0.26 M.

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