The population of a type of local bass can be found using an infinite geometric series where a1 = 72 and the common ratio is one fourth. Find the sum of this infinite series that will be the upper limit of this population.
Sum of infinite sequence is given by S∞ = a/(1 - r); where a is the first term and r is the common ratio.
S∞ = 72/(1 - 1/4) = 72/(3/4) = 96.
Answer:
96
Step-by-step explanation:
Given that the population of a type of local bass can be found using an infinite geometric series.
I term a1 = 72
Common ratio r = \(\frac{1}{4}\)
We know that sum of n terms of geometric series where |r|<1 is
\(S_{n} =\frac{a(1-r^n}{1-r}\)
Sum of infinite terms would be limit of this Sn as n tends to infinity.
When r <1 we have r^n will tend to 0 as n tends to infinity.
Hence Sum of infinite terms
=\(\frac{a}{1-r} =\frac{72}{1-\frac{1}{4} } \\=96\)
Sum of infinite series = 96