What is the centripetal force needed to keep a 3.0 kg mass moving in a circle of radius 0.50 m at a speed of 8.0 m/s
Centripetal acceleration = v²/r = 8²/0.50 = 64/0.50 = 32
Centripetal force = mass acceleration = 3 32 = 96 Newton
So, your answer is 96 Newton
Answer : The centripetal force needed is, 384 N
Solution :
Formula used for centripetal force is,
\(F_c=\frac{m\times v^2}{r}\)
where,
\(F_c\) = centripetal force
m = mass of an object = 3 Kg
r = radius of path
v = velocity or speed of an object
Now put all the given values in the above formula, we get the centripetal force.
\(F_c=\frac{3Kg\times (8m/s)^2}{0.5m}=384Kg\text{ m }s^{-2}=384N\)
Therefore, the centripetal force needed is, 384 N