Verified Answer :

Giangiglia

Answer:

\(C_1_0H_7OH (l) + 23/2 O_2 (g) \longrightarrow 10 CO_2 (g) + 4 H_2O (g)\)  

Explanation:

Hi, the reaction you asked for is the complete combustion of 1-naphthol in which the naphthol reacts with oxygen producing water and carbon dioxide:

\(C_1_0H_7OH (l) + O_2 (g) \longrightarrow CO_2 (g) + H_2O (g)\)

Steps to balance:

1) Number of \(CO_2\) equal to the C in the naphthol:

\(C_1_0H_7OH (l) + O_2 (g) \longrightarrow 10 CO_2 (g) + H_2O (g)\)

2) Number of \(H_2O\)  equal to half the H in the naphthol:

\(C_1_0H_7OH (l) + O_2 (g) \longrightarrow 10 CO_2 (g) + 4 H_2O (g)\)

2) Balance the \(O_2\) equal to O in \(CO_2\) and \(H_2O\) minus the O in the naphthol :

\(C_1_0H_7OH (l) + 23/2 O_2 (g) \longrightarrow 10 CO_2 (g) + 4 H_2O (g)\)  

If you prefer, write the equation in non-fractional numbers:

\(2 C_1_0H_7OH (l) + 23 O_2 (g) \longrightarrow 20 CO_2 (g) + 8 H_2O (g)\)  

Eduard22sly

The balanced chemical equation for the combustion of 1-naphthol, C₁₀H₇OH, to give CO₂ and H₂O is:

2C₁₀H₇OH + 23O₂ —> 20CO₂ + 8H₂O

A combustion reaction is a reaction in which a substance is burned in air i.e oxygen to produce carbon (iv) oxide and water.

The equation for the combustion of 1-naphthol, C₁₀H₇OH can be written as follow:

C₁₀H₇OH + O₂ —> CO₂ + H₂O

The equation above can be balanced as follow:

C₁₀H₇OH + O₂ —> CO₂ + H₂O

There are 10 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 10 before CO₂ as shown below:

C₁₀H₇OH + O₂ —> 10CO₂ + H₂O

There are 8 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 4 before H₂O as shown below:

C₁₀H₇OH + O₂ —> 10CO₂ + 4H₂O

There are a total of 24 atoms of O on the right side and 3 atoms on the left side. It can be balance by writing \(\frac{23}{2}\) before O₂ as shown below:

C₁₀H₇OH + \(\frac{23}{2}\)O₂ —> 10CO₂ + 4H₂O

Multiply through by 2 to clear the fraction

2C₁₀H₇OH + 23O₂ —> 20CO₂ + 8H₂O

Thus, the equation is balanced.

Learn more: https://brainly.com/question/10857449