prove sin^3z*cos^2z=sin^3z-sin^5z
left hand sidesin^3z × ( 1 - sin^2z ) = RHSlet sin z = yy^3 × ( 1 - y^2 ) = RHSy^3 - y^6 = RHSsin^3z - sin^6z = RHSthe answer at RHS should be to the power of 6 . u better check it next time
