How many grams are there in 7.5 X10^23 molecules of H2SO4?
Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of
atoms or molecules into number of moles.
7.5 X10^23 molecules of H2SO4 ( 1 mol / 6.022x10^23 molecules ) (98.08 g / 1 mol ) = 122.15 grams H2SO4
Answer : The mass of \(H_2SO_4\) are, 117.6 grams.
Explanation :
First we have to calculate the moles of \(H_2SO_4\).
As, \(6.022\times 10^{23}\) molecules of \(H_2SO_4\) present in 1 mole of \(H_2SO_4\)
So, \(7.5\times 10^{23}\) molecules of \(H_2SO_4\) present in \(\frac{7.5\times 10^{23}}{6.022\times 10^{23}}=1.2\) mole of \(H_2SO_4\)
Now we have to calculate the mass of \(H_2SO_4\).
\(\text{Mass of }H_2SO_4=\text{Moles of }H_2SO_4\times \text{Molar mass of }H_2SO_4\)
Molar mass of \(H_2SO_4\) = 98 g/mole
\(\text{Mass of }H_2SO_4=1.2mole\times 98g/mole=117.6g\)
Therefore, the mass of \(H_2SO_4\) are 117.6 grams.