Web Analytics
catiesandwich
Answered

How many moles of sulfur are in 23.2 g of (C3H5)2S?
How many atoms of hydrogen are in 0.75 moles of (C3H5)2S?
How many grams of carbon are in 4.20*10^23 molecules of (C3H5)2S?
How many atoms of carbon are in 15.0 g of (C3H5)2S?

Verified Answer :

1)
We have 6 moles of C (2 x3=6), 10 moles of H (2 x 5=10) and 1 mole of S in 1 mole of (C₃H₅)₂S )


The molar mass of (C₃H₅)₂S is 114 g mol

atomic mass (C)=12 u
atomic mass (H)=1 u
atomic mass (S)=32 u

atomic weight ((C₃H₅)₂S )=2[3(12 u)+5( 1 u)]+32 u=114 u

molar mass=value of atomic weigth expres in g/ 1 mol
molar mass ((C₃H₅)₂S )=114 g/mol

we have to find the number of moles  in 23.2 g of (C₃H₅)₂S )
114 g-------------------------1 mol
23.2 g------------------------  x

x=(23.2 g x 1 mol)/114 g≈0.2 moles

We calculate the number of moles of sulfur (S) in 23.2 g (≈0.2 moles) of (C₃H₅)₂S ).

1 mole of (C₃H₅)₂S )------------ 1 mole of S
0.2 moles of (C₃H₅)₂S )-----------    x

x=(0.2 moles of (C₃H₅)₂S ) x 1 mole of S)/1 mole of (C₃H₅)₂S )=0.2 moles

Answer: we have 0.2 moles of sulfur in 23.2 gr of (C₃H₅)₂S )


2)
1 mole of any substance=6.022 x 10²³ atoms or molecules.
We have 10 moles of H in a mole of (C₃H₅)₂S )

1 mole of  (C₃H₅)₂S )----------------------10 moles of H
0.75 moles of (C₃H₅)₂S )------------------  x

x=( 0.75 moles  x  10 moles)/1 mole=7.5 moles

We compute the number of atoms in 7.5 moles of H

1 mole ---------------------------6.022 x 10²³ atoms
7.5 moles------------------------    x

x=(7.5 moles x  6.022 x 10²³ atoms)/1 mole=4.52 x 10²⁴ atoms.

answer: we have 4.52 x10²⁴ atoms of H in 0.75 moles of (C₃H₅)₂S )

3)
We have to calculate the number of moles in 4.20 x 10²³molecules of (C₃H₅)₂S )

1 mole---------------------------6.022 x 10²³ molecules
x-----------------------------------4.20 x 10²³ molecules

x=(1 mole x 4.2010²³)/6.02210²³ molecules≈0.697 moles

we have 72 g of C in 1 mole of (C₃H₅)₂S ).
number of grams in 1 mole of  (C₃H₅)₂S )=2312 g=72 g

1 mole of (C₃H₅)₂S )----------------72 g of C
0.697 moles of (C₃H₅)₂S )----------      x

x=(0.697 moles 72 g)/1 mole≈50.18 g

Answer: there are 50.18 g of C in 4.2010²³ molecules of (C₃H₅)₂S )

4)
We have to calculate the number of moles in 15 g of (C₃H₅)₂S )
 
114 g of (C₃H₅)₂S )-------------------- 1 mole of (C₃H₅)₂S )
15 g of (C₃H₅)₂S )-----------------------   x

x=(15 g 1 mole)/114 g=0.1316 moles of (C₃H₅)₂S )

We calculate the number of moles of C in 0.1316 moles of (C₃H₅)₂S )

1 mole of (C₃H₅)₂S )------------------6 moles of C
0.1316 moles of (C₃H₅)₂S )---------   x

x=(0.1316 moles 6 moles)/1 mole=0.7895 moles

We calculate the number of atoms in 0.7895 moles of C

1 mole of C --------------------------------- 6.02310²³ atoms of C
0.7895 moles of C-------------------------    x

x=(0.7895 moles 6.02210²³)/1 mole≈4.7510²³ atoms.

Answer: there are 4.7510²³ atoms of C in 15 g of (C₃H₅)₂S )


Other way:
We calculate the number of molecules in 15 g of (C₃H₅)₂S )
114 g of (C₃H₅)₂S )---------------6.02310²³ molecules of (C₃H₅)₂S )
15 g of (C₃H₅)₂S )----------------x

x=(15 g 6.02210²³ molecules)/114 g=7.9237 10²² molecules

A molecule of (C₃H₅)₂S ) have 6 atoms of C; therefore
1 molecule---------------------------6 atoms of C
7.9237 10²² molecules-----------    x

x=(7.923710²² molecules 6 atoms)/1 molecule=4.7510²³ atoms

We have the same answer: there are 4.7510²³ atoms of C in 15 g of (C₃H₅)₂S )










boffeemadrid

We need to find the moles of sulfur, the number of atoms, grams of carbon and atoms of carbon in the given samples.

The number of moles of Sulfur is \(0.2031\ \text{moles}\).

The number of atoms of hydrogen is \(4.516\times 10^{24}\ \text{atoms}\)

The mass of carbon is \(79.6\ \text{g}\)

The atoms of carbon in the sample of \((C_3H_5)_2S\) is \(4.73\times 10^{23}\ \text{atoms}\).

Molecular mass of \((C_3H_5)_2S\)

\(2(12.0107\times 3+1.00784\times 5)+32.065=114.2076\approx114.21\)

Mass of sample = 23.2 g

Moles present

\(\dfrac{23.2}{114.21}=0.2031\ \text{moles}\)

The number of moles of Sulfur is \(0.2031\ \text{moles}\).

\(N_A\) = Avogardro's number = \(6.022\times 10^{23}\ \text{mol}^{-1}\)

Moles of hydrogen = 0.75 moles

Number of atoms is given by

\(0.75\times 6.022\times 10^{23}=4.516\times 10^{24}\ \text{atoms}\)

The number of atoms of hydrogen is \(4.516\times 10^{24}\ \text{atoms}\)

Number of molecules of \((C_3H_5)_2S\) is \(4.2\times 10^{23}\)

Moles of \((C_3H_5)_2S\)

\(\dfrac{4.2\times 10^{23}}{6.022\times 10^{23}}=0.697\ \text{moles}\)

Mass of carbon is

\(0.697\times 114.21=79.6\ \text{g}\)

The mass of carbon is \(79.6\ \text{g}\).

Mass of \((C_3H_5)_2S\) is 15 g

Moles of \((C_3H_5)_2S\) present in the sample is

\(\dfrac{15}{114.21}=0.131\)

Moles of carbon is

\(0.131\times 2\times 3=0.786\)

Atoms of carbon

\(0.786\times 6.022\times 10^{23}=4.73\times 10^{23}\ \text{atoms}\)

The atoms of carbon in the sample of \((C_3H_5)_2S\) is \(4.73\times 10^{23}\ \text{atoms}\).

Learn more:

https://brainly.com/question/20484279

https://brainly.com/question/27130

Related Questions