fith2Amalovelardock fith2Amalovelardock

06-11-2016
Physics

Answered

When a 2.50 kg object is hung vertically on a certain light spring described by hookes law the spring stretches 2.76 cm.

Awhat is the force constant of the spring.
Bif the 2.50?

Verified Answer :

austinbaird austinbaird

12-11-2016

F=KX,
F=Ma

Ma=KX

2.59.81=K0.0276

24.525=K*0.0276

24.525/0.0276=K

K= 888.6 N/m ---- force constant

assuming 2.5 refers to the new extension, just divide F/ 0.025
to get

981N/m

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