Answer:
The chemical reaction is given as:
\(PbI_2+2CH_3COOK\rightarrow Pb(CH_3COO)_2+2KI\)
Explanation:
When lead acetate reacts with potassium iodide it gives lead iodide and potassium as acetate as products.
The chemical reaction is given as:
\(PbI_2+2CH_3COOK\rightarrow Pb(CH_3COO)_2+2KI\)
According to reaction, 1 mole of lead iodide reacts with 2 moles of potassium acetate to form 1 mole of lead acetate and 2 moles of potassium iodide.
