A 28000 kg railroad freight car collides with a stationary caboose car. They couple together, and 20 percent of the initial kinetic energy is dissipated as heat, sound, vibrations, and so on. What is the mass of the caboose?

Verified Answer :

we have to conserve momentum:

initial p = final p

28000kg u + 0 = (28000kg + M) v

so u = (28000 + M)v / 28000

and u² = (28000 + M)²
v² / 28000²


Initial KE = ½ 28000kg u² = 14000kg u²

Final KE = ½
(28000kg + M) v² = 0.8 Initial KE = 11200kg u²

Substitute for u² and use k = 28000 for now:

½
(k + M) v² = 11200 (k + M)² v² / k² → (k + M) v² CANCELS!

½ = 11200 (k + M) / k²

k² = 22400
(k + M) = 22400k + 22400M → replace k

28000² - 22400*28000 = 22400M

M = 7000 kg
hope it helps