The sum of two numbers is 20. four times the larger is one less than five times the smaller. what are the numbers?
your larger number is 11 and your smaller one is 9. You solve this by first dividing 20 in half. Then you make one larger than the other by subtracting 1 from one 10 and adding adding that subtracted 1 to the other 10. Then you multiply 11 by 4 (11×4) and get 44 then multiply 9 by 5 (9×5) and get 45. Then subtract 44 from 45 (45-44) and the difference is 1.
n → smaller
20 - n → larger
4 (20 - n) = 5n - 1
80 - 4n = 5n - 1
81 = 9n
n = 9
20 - n = 11
Therefore, the numbers are 9 and 11.