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Verified Answer :

syed514

a)He can cut 5 strips of of 7/10m.

7/10=0.7m

0.7*5=3.5m 
3.5m of wire wil be used in cutting possible 7/10m pieces.

b)Leftover will be 0.6m.
4.1-3.5=0.6m


calculista

we know that
\(4.1m= \frac{41}{10}m\)

Part a) how many strip 7/10m long can he cut?

divide \(\frac{41}{10}\) by \(\frac{7}{10}\)
so
\(\frac{ \frac{41}{10}}{ \frac{7}{10}} = \frac{41}{7} \\ \\ =5.85 \\ \\ =5strip\)

the answer part a) is
\(5strip\)

Part b) how much wire will he have left over
\(5* \frac{7}{10} =3.5m\)
\(3.5\)m of wire wil be used in cutting possible \(\frac{7}{10}\)m pieces

so
wire left over will be
\(4.1-3.5=0.6 m\)

the answer Part b) is 
\(0.6m\)

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