Answer:
m = 12.6 kg
Explanation:
As we know that it covers total distance of 2.3 m in 1.3 s
so we will have
\(v_i = 0\)
\(d = 2.3 m\)
\(t = 1.3 s\)
now we can use kinematics to find the acceleration
\(d = v_i t + \frac{1}{2}at^2\)
\(2.3 = \frac{1}{2}a(1.3^2)\)
\(a = 2.72 m/s^2\)
Now we can use Newton's law
\(F = ma\)
\(34.3 = m(2.72)\)
\(m = 12.6 kg\)
