Answer:
\((x+2)^2+(y-5)^2=16\)
Step-by-step explanation:
We have been given that a circle has its center at (−2, 5) and a radius of 4 units. We are asked to write the equation of the circle.
We know that standard equation of circle is in form \((x-h)^2+(y-k)^2=r^2\), where, (h,k) represents vertex of circle and r represents radius of circle.
Upon substituting coordinates of vertex \((-2,5)\) and \(r=4\) in above equation, we will get:
\((x-(-2))^2+(y-5)^2=4^2\)
\((x+2)^2+(y-5)^2=16\)
Therefore, the equation of our given circle would be \((x+2)^2+(y-5)^2=16\).
