A student takes an exam containing 18 true or false questions. If the student guesses, what is the probability that he will get exactly 6 questions right? Round your answer to four decimal places.

Verified Answer :

use this formula.
and solution is:[(18!)/(6!×(18-6)!)]×(1/2)^6×(1-1/2)^(18-6)≈0.0781604
7.8%

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The probability that he will get exactly 6 questions right is 0.0708

What is probability?

"Probability is a branch of mathematics which deals with finding out the likelihood of the occurrence of an event."

Formula of the probability of an event A is:

P(A) = n(A)/n(S)

where,  n(A) is the number of favorable outcomes, n(S) is the total number of events in the sample space.

What is the formula of combination?

"\(^nC_r=\frac{n!}{r!(n-r)!}\)"

What is Binomial distribution formula of probability?

\(P=^nC_x\times (p)^x\times (q)^{n-x}\)

where p : probability of success

q: probability of failure

x: number of times for a specific outcome within n trials

n: number of trials

For given question,

A student takes an exam containing 18 true or false questions.

So, n = 18

The probability of success is \(p=\frac{1}{2}\)

So, the probability of failure would be,

\(q= 1-p\\\\q=1-\frac{1}{2} \\\\q=\frac{1}{2}\)

We need to find the probability that the student will get exactly 6 questions right .

Using Binomial distribution theorem,

\(P=^nC_x\times (p)^x\times (q)^{n-x}\\\\P=^{18}C_6\times (\frac{1}{2})^6\times (\frac{1}{2})^{18-6}\\\\P=18564 \times (\frac{1}{2})^6\times (\frac{1}{2})^{12}\\\\P=18564\times \frac{1}{262144}\\\\P=\frac{4641}{65536}\\\\P=0.0708\)

Therefore, the probability that he will get exactly 6 questions right is 0.0708

Learn more about probability here:

brainly.com/question/11234923

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