The Standard form of \(8x^2y^2 - \frac{3x^3y}{2} + 4x^4 - 7xy^3\) will be \(-7xy^3 + 8x^2y^2 - \frac{3x^3y}{2} + 4x^4\) .
What is Standard form ?
Standard form means that the terms are ordered from biggest exponent to lowest exponent.
We have,
\(8x^2y^2 - \frac{3x^3y}{2} + 4x^4 - 7xy^3\)
To write it in standard form we will first simplify the polynomial and then arrange in standard form.
\(8x^2y^2 - \frac{3x^3y}{2} + 4x^4 - 7xy^3\)
Now,
As we see polynomial, \(y\) have highest exponent as well as constant term \(4x^4\) as it do not have \(y\) with it.
So,
Move \(-7xy^3\) toward left hand;
\(- 7xy^3+8x^2y^2 - \frac{3x^3y}{2} + 4x^4\)
So, the obtained polynomial is the standard form of the given polynomial.
Hence, we can say that the Standard form of \(8x^2y^2 - \frac{3x^3y}{2} + 4x^4 - 7xy^3\) will be \(-7xy^3 + 8x^2y^2 - \frac{3x^3y}{2} + 4x^4\) .
To know more about standard form click here
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