Find the range of the function f(x)=(x+5)^2+8
finding the vertex of the parabolay = (x + 5)^2 + 8 the vertex is at (-5, 8)its coefficient so the parabola turns upward so the range is [8 , inf]
f(x) = x²+10x+25+8f(x) = x²+10x+33