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If there were 30,000 cars produced and later it was found that 222 had a defect in one of the headlight bulbs, what is the probability that any one of

those cars would have the defect?

A1/5200
B37/5000
C2/6235
D10/520

Verified Answer :

degraaf23
Bcause 222/30,000 you divide them both by 5 and you get 37/5000
Blacklash

Answer:

Option B is the correct answer.

Step-by-step explanation:

Probability is ratio of number of favorable outcome to total number of outcomes.

Number of cars produced = Total number of outcomes = 30000

Number of defective cars = Number of favorable outcome = 222

\(\texttt{Probability}=\frac{222}{30000}=\frac{111}{15000}=\frac{37}{5000}\)

Option B is the correct answer.

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