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philliptusler88
Answered

The distribution of vitamin C amount in vitamin drops produced by a given factory is approximately Normal, with a mean of 60.0 mg and a standard deviation of 0.5 mg.


About 80% of vitamin drops contain more than

A 59.36 mg of vitamin C.

B 59.58 mg of vitamin C.

C 60.42 mg of vitamin C.

D 60.64 mg of vitamin C.

Verified Answer :

You have to calculate z-scores for each of these values and then compare them with what is needed for the 80%tile on a Normal curve.

 
z = (value - mean)/(standard deviation) = (value-60.0)/0.5.
z= 1 has 84% of the values smaller.

gbenewaeternity

Answer:

The correct answer is option (B) 59.58 mg of vitamin C.

Step-by-step explanation:

See the attached file for the calculation

View image gbenewaeternity

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