sh0ionRegirl sh0ionRegirl

04-11-2016
Mathematics

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cosA x cos2A x cos4A x cos8A = sin16A/16sinA

Verified Answer :

alsteva alsteva

11-11-2016

Given cosA x cos2A x cos4A x cos8A = sin16A/16sinA

RHS

sin16A/16sinA

[2sin8A cos 8A]/16sinA

[cos8A(2sin4A cos4A)]/8sinA

[cos8A cos 4A(2 sin 2A cos 2A)]/4sinA

[cos 8A cos 4A cos 2A(sin2A)]/2 sinA

[cos8A cos 4A cos 2A(2sinA cos A)]/2
sin A
cos A cos 2A cos 4A cos 8A

Hence RHS=LHS

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