The product of the roots of 8x_ - 2x = 1 is
\(\\8x^2-2x-1=0 \\8x^2-4x+2x-1=0 \\4x(2x-1)+1(2x-1)=0 \\(4x+1)(2x-1)=0\)Roots are \(x=- \frac{1}{4}\) and \(x= \frac{1}{2}\)\(- \frac{1}{4} \times \frac{1}{2} =- \frac{1}{8}\)