What is the equation in point-slope form of the line passing through (0, 5) and (_2, 11)?
Point (0,5) lies on the y-axis. Therefore, y-intercept is 5 (n=5). A line passes through the point (-2,11). Therefore, x=-2 and y=11. Substitute these values in the equation of line to find slope m.
\(y=mx+n
\\11=m(-2)+5
\\6=-2m
\\m=-3\)
The equation of line is \(y=-3x+5\)