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Consider the following reaction:

NH4HS(s)_NH3(g)+H2S(g)

An equilibrium mixture of this reaction at a certain temperature was found to have [NH3]= 0.272M and [H2S]= 0.365M .


What is the value of the equilibrium constant (Kc) at this temperature?

Verified Answer :

Answer : The equilibrium constant is, \(9.928\times 10^{-2}\)

Solution : Given,

Equilibrium concentration of \(NH_3\) = 0.272 M

Equilibrium concentration of \(H_2S\) = 0.365 M

The given balanced equilibrium reaction is,

\(NH_4HS(s)\rightleftharpoons NH_3(g)+H_2S(g)\)

The expression for equilibrium constant will be,

\(K_c=\frac{[NH_3][H_2S]}{[NH_4HS]}\)

Now put all the given values in this formula, we get  value of equilibrium constant.

\(K_c=\frac{(0.272)\times (0.365)}{1}\)

\(K_c=0.09928=9.928\times 10^{-2}\)

Therefore, the equilibrium constant is, \(9.928\times 10^{-2}\)